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# sum of even,odd numbers

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 Submitted on: 2/15/2011 1:03:17 PM By: lakshmi.G Level: Beginner User Rating: By 2 Users Compatibility: C Views: 2945

This code is useful to compute the sum of odd , even numbers and both upto certain limit.

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 Terms of Agreement:    By using this code, you agree to the following terms...    You may use this code in your own programs (and may compile it into a program and distribute it in compiled format for languages that allow it) freely and with no charge. You MAY NOT redistribute this code (for example to a web site) without written permission from the original author. Failure to do so is a violation of copyright laws.    You may link to this code from another website, but ONLY if it is not wrapped in a frame.  You will abide by any additional copyright restrictions which the author may have placed in the code or code's description. ``` //************************************** // Name: sum of even,odd numbers // Description:This code is useful to compute the sum of odd , even numbers and both upto certain limit. // By: lakshmi.G // //This code is copyrighted and has// limited warranties.Please see http://www.Planet-Source-Code.com/vb/scripts/ShowCode.asp?txtCodeId=13403&lngWId=3//for details.//************************************** #include #include void main() { int n,se=0,so=0,ch,i; clrscr(); printf("enter the number limit:"); scanf("%d",&n); printf("\n1.odd\n2.even\n3.both\n"); printf("enter your choice of displaying the result:"); scanf("%d",&ch); for(i=0;i<=n;i++) { if(i%2==0) se=se+i; } for(i=0;i<=n;i++) { if(i%2!=0) so=so+i; } switch(ch) { case 1: printf("\nsum of even numbers=%d",se); break; case 2: printf("\nsum of odd numbers=%d",so); break; case 3: printf("\nsum of even numbers=%d",se); printf("\nsum of odd numbers=%d",so); printf("\nsum of both numbers=%d",(so+se)); break; default: printf("\nenter a valid choice\n"); } getch(); } ```

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