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output elements in array without repitition

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Submitted on: 8/30/2012 12:15:06 PM
By: Thejwal P 
Level: Intermediate
User Rating: Unrated
Compatibility: C++ (general)
Views: 919
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     you give in an array with repeating elements and get all the elements in the array without repitition
 
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//**************************************
// Name: output elements in array without repitition
// Description:you give in an array with repeating elements and get all the elements in the array without repitition
// By: Thejwal P
//
//This code is copyrighted and has// limited warranties.Please see http://www.Planet-Source-Code.com/vb/scripts/ShowCode.asp?txtCodeId=13832&lngWId=3//for details.//**************************************

#include<iostream.h>
#include<stdio.h>
void count(int input1[],int);
int main()
{
	int size;
	
	cout<<endl<<"ENTER SIZE OF ARRAY";
	cin>>size;
	int input[size];
	
	cout<<endl<<"ENTER ELEMENTS OF AN ARRAY TO LIST THE NUMBERS IN IT WITHOUT REPITITION"<<endl;
	
	for(int i=0;i<size;i++)
	cin>>input[i];
	
	
	count(input,size);	
	
}
void count(int input[],int size)
{
	int record[size],j; //note:record array keeps a record of the elements encounterd
	//for(int i=0;i<size;i++)
	//record[i]=0;
	
	int match=0;
	
	int i,d,index=0;
	
	for(i=0;i<size;i++) //take the elements in input array one by one for comparing with record array
	{
		//cout<<endl<<"input["<<i<<"]="<<input[i];
		match=0; //set flag variable in case the number is already recorded in the record array
		
		for(j=0;j<index;j++)
		{
			//cout<<endl<<"record["<<j<<"]="<<record[j];
			if(input[i]==record[j])
			{
			//cout<<endl<<record[j];
			match=1;
			break;
			 //if match set flag vaiable
			}
		}	
		
		if(match==0) // if no record of the element has been made yet copy it into the record
		record[index++]=input[i];	
		//cout<<endl<<"j="<<j;
	}
		
	
	
	for(i=0;i<index;i++)
	cout<<endl<<record[i];
}


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