 # Invert Number Formula - "One liners" Email
 Submitted on: 10/12/2018 1:22:37 AM By: Nicholas Forystek Level: Beginner User Rating: Unrated Compatibility: VB 3.0, VB 4.0 (16-bit), VB 4.0 (32-bit), VB 5.0, VB 6.0 Views: 7066 This function is to invert a number using a mathematical formula, by default in a whole of 100 for percentages with a unit defined size of 1. Example if you call InvertNum(25) the result is 75, and InvertNum(50) is 50. All function I understand require at least 3 lines of code, but it's not so true, regarding running, as to the inheritance reference, so maybe just write it out each time is really just one line, with out the function header footer, so that I may have helped one day explain.

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 ``` '************************************** ' Name: Invert Number Formula - "One liners" ' Description:This function is to invert a number using a mathematical formula, by default in a whole of 100 for percentages with a unit defined size of 1. Example if you call InvertNum(25) the result is 75, and InvertNum(50) is 50. All function I understand require at least 3 lines of code, but it's not so true, regarding running, as to the inheritance reference, so maybe just write it out each time is really just one line, with out the function header footer, so that I may have helped one day explain. ' By: Nicholas Forystek '************************************** Public Function InvertNum(ByVal Value As Long, Optional ByVal Whole As Long = 100, Optional ByVal Unit As Long = 1) InvertNum = -(Whole / Unit) + -(Value / Unit) + ((Whole / Unit) * 2) End Function ```

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